dsm_gsx97
July 11th, 2006, 08:42 AM
After writing this all out in another thread (9SR dyno day thread) I thought it would be useful for everyone so they can judge what size of injectors and pump they'd need for the amount of HP they want to put out.
Values I'm using in these calculations are a 20% safty margin (part of the math) and that the BSFC of our cars is .65. I did 700hp (for Shawn) as the example for this calculation.
The equations to determine your fuel requirement is as follows:
? (Power x BSFC) x (1 + Safety Margin) = pounds/hour
? Pounds/hour / 7.25 = gallons/hour.
? 3.785l/gallon (only for fuel pump numbers since they're in liters)
Then...
? ((Power x BSFC) x (1 + Safety Margin))/Number of Injectors = pounds/hour
? cc/min = lbs/hr x 9.71
So...with 20% safty margin for injector duty and fuel pump
(700hp x BSFC = .65) x 1.20 = 546 lbs./hr.
546 lbs./hr. / 7.25 = 75.31 gallons/hour
75.31 gallons x 3.785 liters = 285.05 liters/hour (only needed for fuel pump flow numbers)
So...for injector size
546 lbs./hr. (copied from above) / 4 = 136.5 lbs/hr
cc/min = 136.5 x 9.71 = 1325.42 cc/min
Values I'm using in these calculations are a 20% safty margin (part of the math) and that the BSFC of our cars is .65. I did 700hp (for Shawn) as the example for this calculation.
The equations to determine your fuel requirement is as follows:
? (Power x BSFC) x (1 + Safety Margin) = pounds/hour
? Pounds/hour / 7.25 = gallons/hour.
? 3.785l/gallon (only for fuel pump numbers since they're in liters)
Then...
? ((Power x BSFC) x (1 + Safety Margin))/Number of Injectors = pounds/hour
? cc/min = lbs/hr x 9.71
So...with 20% safty margin for injector duty and fuel pump
(700hp x BSFC = .65) x 1.20 = 546 lbs./hr.
546 lbs./hr. / 7.25 = 75.31 gallons/hour
75.31 gallons x 3.785 liters = 285.05 liters/hour (only needed for fuel pump flow numbers)
So...for injector size
546 lbs./hr. (copied from above) / 4 = 136.5 lbs/hr
cc/min = 136.5 x 9.71 = 1325.42 cc/min